AOJ Volume11-1137

Problem C: Numeral System
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=1137&lang=jp

ICPCの過去問
解法:解析->複合

#include<iostream>
#include<cmath>
#include<sstream>
#include<string>

using namespace std;

//string型の数字をint型にして返すよ
int s_to_int(string s) {
	stringstream ss;
	int n;
	ss << s;
	ss >> n;
	return n;
}

//cが1文字の整数かどうか返すよ
bool num_check(char c){ return c >= 48 && c <= 57;}

//文字ごとに桁数返すよ
int check(char c) {
	if (c == 'm') {
		return 1000;
	}else if (c == 'c') {
		return 100;
	}else if (c == 'x') {
		return 10;
	}else {
		return 1;
	}
}

int main() {
	int n=0;
	cin >> n;
	for (int i=0; i < n; i++) {
		int sum = 0;
		//解析
		for (int j=0; j < 2; j++) {
			string s;
			cin >> s;
			for (int k=0; k < s.size(); k++) {
				if (num_check(s[k])) {
					string hs = "";
					hs += s[k];
					int hn = s_to_int(hs);
					sum += hn * check(s[k+1]);
					k++;
				}else {
					sum += 1 * check(s[k]);
				}
			}
		}
		
		//sumを元に暗号化
		int num[] = {0,0,0,0};
		char c_num[] = {'m','c','x','i'};
		int count = 0;
		for (int h = 1000; h != 1; h/=10) {
			if(sum >= h) {
				num[count] = (int) floor(sum / h);
				sum -= num[count] * h;
			}
			count++;
		}
		num[3] = (int) sum;
		
		string resurt = "";
		
		for (int h=0; h < 4; h++) {
			if (num[h] >= 1) {
				if (num[h] != 1) resurt += num[h]+48;
				resurt += c_num[h];
			}
		}
		
		cout << resurt << endl;
		
	}
	
}